This problem should be discussed in two situations. First, the oxide charge density at the flat-band condition. By using this formula: The value of Qox is -1.045* 10 6 C/cm 2 Then, we can use this formula to calculate the count of charges. We know the value of q, this is a common value, 1.602*10 -19 Then the value of N OX is 6.52*10 12 Second, at mid-gap situation, we need different formulas to calculate the value of Q OX , and there are the formulas: After calculate the value of VG , deltaV is 0.422-1.35=-0.928V, and we also knew the value of area, so Q OX is -1.14*10 -6 C/cm 2 In the end, the value of N OX at mid-gap condition is 7.116*10 12